14w+w^2+30=0

Solution for 14w+w^2+30=0 equation:

14w+w^2+30=0

a = 1; b = 14; c = +30;
Δ = b2-4ac
Δ = 142-4·1·30
Δ = 76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{76}=\sqrt{4*19}=\sqrt{4}*\sqrt{19}=2\sqrt{19}$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{19}}{2*1}=\frac{-14-2\sqrt{19}}{2}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{19}}{2*1}=\frac{-14+2\sqrt{19}}{2}
$